There is FOUR parts to this question. (A, B, C, & D) ANSWER ALL PARTS. SHOW YOUR

Question

There is FOUR parts to this question. (A, B, C, & D) ANSWER ALL PARTS. SHOW YOUR WORK, CLEARLY!

2) weak DIPSO (pka = 7.60) is a commonly used in biochemistry labs to make buffers. The acid Show all of your calculations clearly and with correct units and significant figures . a. What is the Ka of DIPSO? b. What is the pH of the 0.50OM solution of DIPSO from part (a) The small x approximation may be used. C. What ratio of the conjugate base to weak acid is needed to create a DIPSO buffer with a pH of 7.00? d. How many would need added to 1-0pH 00? moles of NaOH to be L of 50OM DIPSO to obtain a of 7.

Explanation / Answer

PKa = -log ka

A. ka= 10-7.6

B. we know for weak acid solution

pH = PKA+ 1/2 log c = 7.6+1/2 log 0.5

C. ACCORDING TO HENDERSON EQUATION

pH= PKA+ log salt/ acid= 7.6+ log x

7= 7.6 + log x

x= 10-0.6

D. 7= 7.6+ log (Y/1x.5)

by evaluating y we can get the moles of NaOH: THE EQUATION RELATES THE EQUIVALENCE FORM OF SALT AND BASE

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