The following diagram represents the reaction of A_2 (dark spheres) with B_2 (li

Question

The following diagram represents the reaction of A_2 (dark spheres) with B_2 (light spheres) Write a balanced equation for the reaction, and circle the species in your equation that is the limiting reactant. How many moles of product can be made from 1.0 mol of A_2 and 1.0 mol of B_2? Box (a) represents 1.0 mL of a solution of molecules at a given concentration. Circle the box (b, c, or d) that represents 1.0 mL of the solution that results after (a) has been diluted by doubling the volume of the solvent.

Explanation / Answer

7. In the reactant box both types of molecules are dimoleculea. There are 4 A2 molecules. That means 8 A atoms. There are 6 B2 molecules. That means 12 B molecules. So in the product box all the reactant molecules or the atoms should be there. There are4 compounds those contain 1 A atom circled by 3 B atoms. And there are 2 seperate A2 molecule in the product box. By this A2 molecules in the product box we can say those molecules are unreacted ones. Now we can write the balanced equation as below.

4A2 + 6B2 --> 4B3A + 2A2

We can symplify this furthermore

2A2 + 3B2 --> 2B3A + A2

Here there are 2 unreacted A2 molecules in the product box. We can say that Bs are not enough to make B3A molecules. Therefore B2 is the limiting factor. A2 : B2 = 2:3

if we take 1 moles from borth molecules and cobsider B2 as the limiting factor;

No of moles of A2 required for reaction = (1×2)/3 = 0.666 mol.

A2 : B3A = 2:2= 1:1

Therefore the product B3A molecule is o.666 moles.

8. Diluting is increasing of water molecules in the mixture and reducing its concentration. For dilution by doubling initial concentration gets lower 2 times. As an example if initial concentration is C after diluting doubling final concentration is C/2.

Here the dilution is done by increasing the volume. If we compare the no of molecules in the two systems,no change of molecules can be observed. Therefore c can be the answer.

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