Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Specify both the alcohol starting materials and the reagents you would use in ea

ID: 1002892 • Letter: S

Question

Specify both the alcohol starting materials and the reagents you would use in each step in a synthesis of the compound shown. If the synthesis requires only two steps, enter "none" for step 3 Write the number/letters of the alcohol/reagents in the boxes bellow. P1A). Alcohol starting material________P1B). Reagent for step1_______P1C). Reagent for step 2______P1D). Reagent for step 3________Write the number/letters of the alcohol/reagents in the boxes below P2A). Alcohol starting material________P2B). Reagent for step1_______P2C). Reagent for step 2______P2D). Reagent for step 3________Specify the reagent you would use in each step of the following synthesis: Write the letters of the reagents in the boxes below. P3A). Reagent for step 1_________P3B) Reagent for step 2_________

Explanation / Answer

Answer – We are given the alkene product and we need to look for the starting alcohol and then reagent used for conversion of the alcohol to alkene.

P1) In this one there is alkene with cyclohexane ring, so we need starting alcohol is cyclohexanol.

Then this cyclohexanol reacts with CrO3 and H2SO4 give the cyclohexanone. Then this cyclohexanone reacts with propyl magnesium bromide and form the alcohol again. Then using the H2SO4 there is form the given alkene.

P1 A) 5. Cyclohexanol

P1 B) Reagent for step 1 – g,b

P1 C) Reagent for step 2 – k

P1 D) Reagent for step 3 – b

P2) In this one there is starting alcohol need to use is 2-propanol.

Then this 2-propanol reacts with CrO3 and H2SO4 give the propanone. Then this propanone reacts with propyl magnesium bromide and form the alcohol again. Then using the H2SO4 there is form the given alkene.

P2 A) 4. 2-propanol

P2 B) Reagent for step 1 – g,b

P2 C) Reagent for step 2 – k

P2 D) Reagent for step 3 – b

P3) In this one there is given aldehyde and it is converted to alkyl halide. First given aldehyde reacts with ethyl magnesium bromide and then there is formed alcohol as product. Then this alcohol reacts with SOCl2 so there is formed halogenating product as follow –

P3 A) Reagent for step 1 - k

P3 B) Reagent for step 2- e

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote