In lab you determined the volume of 12 marbles and the mass of 18.0 mL of water.
ID: 1003153 • Letter: I
Question
In lab you determined the volume of 12 marbles and the mass of 18.0 mL of water. Use the following data, which should closely approximate your results, to answer the questions below. Mass of 18.0 mL of water 18.01 g Mass of 12 marbles (from Data Table B) WebAssign will check your answer for the correct number of significant figures. g Volume of 12 marbles 19.6 mL (a) What are the densities determined from the data above? water WebAssign will check your answer for the correct number of significant figures. g/mL marbles WebAssign will check your answer for the correct number of significant figures. g/mL(b) The number of moles of water present in 18.01 g of water is WebAssign will check your answer for the correct number of significant figures. mol.
(c) Use scientific notation for the number of water molecules in 18.01 g of water. (Enter your answer using the format 2.2e21 for 2.2 1021.) WebAssign will check your answer for the correct number of significant figures. molecules
(d) What is the mass of a single molecule of water? WebAssign will check your answer for the correct number of significant figures. g
(e) How many water molecules would have the mass of one marble? WebAssign will check your answer for the correct number of significant figures. molecules
(f) Neglect empty space between molecules and calculate the average volume of a water molecule. WebAssign will check your answer for the correct number of significant figures. mL
(g) What is the average volume of a marble? WebAssign will check your answer for the correct number of significant figures. mL
(h) How many water molecules could fit in the same volume as one marble?
In lab you determined the volume of 12 marbles and the mass of 18.0 mL of water. Use the following data, which should closely approximate your results, to answer the questions below. Mass of 18.0 mL of water 18.01 g Mass of 12 marbles (from Data Table B) WebAssign will check your answer for the correct number of significant figures. g Volume of 12 marbles 19.6 mL (a) What are the densities determined from the data above? water WebAssign will check your answer for the correct number of significant figures. g/mL marbles WebAssign will check your answer for the correct number of significant figures. g/mL
(b) The number of moles of water present in 18.01 g of water is WebAssign will check your answer for the correct number of significant figures. mol.
(c) Use scientific notation for the number of water molecules in 18.01 g of water. (Enter your answer using the format 2.2e21 for 2.2 1021.) WebAssign will check your answer for the correct number of significant figures. molecules
(d) What is the mass of a single molecule of water? WebAssign will check your answer for the correct number of significant figures. g
(e) How many water molecules would have the mass of one marble? WebAssign will check your answer for the correct number of significant figures. molecules
(f) Neglect empty space between molecules and calculate the average volume of a water molecule. WebAssign will check your answer for the correct number of significant figures. mL
(g) What is the average volume of a marble? WebAssign will check your answer for the correct number of significant figures. mL
(h) How many water molecules could fit in the same volume as one marble?
In lab you determined the volume of 12 marbles and the mass of 18.0 mL of water. Use the following data, which should closely approximate your results, to answer the questions below. Mass of 18.0 mL of water 18.01 g Mass of 12 marbles (from Data Table B) WebAssign will check your answer for the correct number of significant figures. g Volume of 12 marbles 19.6 mL (a) What are the densities determined from the data above? water WebAssign will check your answer for the correct number of significant figures. g/mL marbles WebAssign will check your answer for the correct number of significant figures. g/mL
(b) The number of moles of water present in 18.01 g of water is WebAssign will check your answer for the correct number of significant figures. mol.
(c) Use scientific notation for the number of water molecules in 18.01 g of water. (Enter your answer using the format 2.2e21 for 2.2 1021.) WebAssign will check your answer for the correct number of significant figures. molecules
(d) What is the mass of a single molecule of water? WebAssign will check your answer for the correct number of significant figures. g
(e) How many water molecules would have the mass of one marble? WebAssign will check your answer for the correct number of significant figures. molecules
(f) Neglect empty space between molecules and calculate the average volume of a water molecule. WebAssign will check your answer for the correct number of significant figures. mL
(g) What is the average volume of a marble? WebAssign will check your answer for the correct number of significant figures. mL
(h) How many water molecules could fit in the same volume as one marble?
Explanation / Answer
Solution:- (a) mass of water = 18.01 g
volume of water = 18.0 ml
we know that, density = mass/volume
so, density of water = 18.01 g/18.0ml = 1.00 g/ml
(18.01 has four sig figs and 18.0 has only three sig figs. So, the answer has to have 3 sig figs)
to calculate the density of marbles we need the mass which is not given here. So, it could not be calculated.
(b) 18.01 g is the molar mass of water means it is the mass of 1 mol of water. Hence the number of moles with correct sig figs would be 1.000
so, answer is 1.000 mol.
(c) 1 mol of anything equals Avogardo number which is 6.022 x 1023 molecules.
So, far we have converted grams into mol and we got 1.000 mol.
so, 1.000 mol of water would be 6.022 x 1023 molecules.
(d) 18.01 g is the mass of 6.022 x 1023 water molecules.
So, 1 molecule x (18.01g/6.022 x 1023 molecules) = 2.991 x 10-23 g
(e) To solve this part we need mass of marbles which is not given so it could not be solved.
(f) 18.0 ml is the volume of 6.022 x 1023 molecules.
1 molecule x (18.0 ml/6.022 x 1023 molecules) = 2.99 x 10-23 ml
(g) Volume of 12 marbles is 19.6 ml.
So, 1 marble x (19.6 ml/12 marbles) = 1.6 ml
(h) 1.6 ml x (1 water molecule/2.99 x 10-23 ml) = 5.4 x 1022 water molecules
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