Consider the reaction A(g) + B(g) C(g) + D(g) K_c = 25.0 Starting with (A) = 0.2

Question

Consider the reaction A(g) + B(g) C(g) + D(g) K_c = 25.0 Starting with (A) = 0.200 M, (B) = 0.200 M, (C) = 0.600 M, (D) = 0.600 at 27 degree C Determine the equilibrium concentrations of all species. Starting with (A) = 1.00 M, (B) = 2.00 M, (C) = 10.0 M, (D) = 12.0 M Determine the equilibrium concentrations of all species. Consider the reaction 2A(g) B(g) + C(g) K_c =1.44 Starting with (A) = 0.500 M, (B) = 0.100 M, (C) = 0.100 M Determine the equilibrium concentrations of all species Starting with (A) = 2.00 M, (B) = 5.00 M, (C) = 6.00

Explanation / Answer

a)        A (g) + B (g) ------> C (g) + D (g)
initially 0.2       0.2          0.6 0.6
at equi   (0.2-x) (0.2-x)       (0.6+x) (0.6+x)
Kc = [C][D]/[A][B]
25 = ((0.6+x)*(0.6+x))/((0.2-x)*(0.2-x))
x = 0.4
at euilibrium [A] = 0.2 - 0.4 = -0.2
[B] = 0.2 - 0.4 = -0.2
[C] = 0.6 + 0.4 = 1
[D] = 0.6 + 0.4 = 1
b)
       A (g) + B (g) ------> C (g) + D (g)
initially 1        3            10    12
at equi   (1-x)   (3-x)        (10+x) (12+x)
Kc = [C][D]/[A][B]
25 = ((10+x)*(12+x))/((1-x)*(3-x))
x = 5.4287
at equilibrium [A] = 1 - 5.4287 = -4.4287
[B] = 3 - 5.4287 = -2.4287
[C] = 10 + 5.4287 = 15.4287
[D] = 12 + 5.4287 = 17.4287
c)
                   2A (g) ------> B (g) + C (g)
initially       0.5             0.1      0.1
at equil (0.5 - 2x)     (0.1 +x) (0.1 +x)
Kc = [C][D]/[A]^2
1.44 = ((0.1 +x)*(0.1 +x))/((0.5 - 2x)^2)
x = 0.5
at equil [A] = (0.5 - 2 *0.5)^2 = 0.5
[B] = 0.1 + 0.5 = 0.6
[C] = 0.1 + 0.5 = 0.6
d)
         2A (g) ------> B (g) + C (g)
initially     2                     5       6
at equil   (2 - 2x)       (5 +x) (6 +x)
Kc = [C][D]/[A]^2
1.44 = ((5 +x)*(6 +x))/((2 - 2x)^2)
x = 5.6348
at equil [A] = (2 - 2 *5.6348)^2 = 85.925
[B] = 5 + 5.6348 = 10.6348
[C] = 6 + 5.6348 = 11.6348

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