The following reaction has a K value equal to 2.95 at 800o. CH4(g) + 2H2S(g) CS2
ID: 1005182 • Letter: T
Question
The following reaction has a K value equal to 2.95 at 800o. CH4(g) + 2H2S(g) CS2(g) + 4H2(g) For each of the following compositions, decide whether the reaction mixture is at equilibrium. If it is not, decide which direction the reaction should go. (a) [CH4] = 1.25 atm [H2S] = 1.08 atm [CS2] = 0.95 atm [H2] = 1.95 atm (b) [CH4] = 1.15 atm [H2S] = 1.28 atm [CS2] = 1.51 atm [H2] = 1.22 atm
2. Nitric oxide, NO, is formed in automobile exhaust by the reaction of N2 and O2:
N2(g) + O2(g) 2NO(g)
The equilibrium constant is 0.0025 at 2127OC. If an equilibrium mixture at this temperature contains 5.3 x 10-2 atm of N2, and 2.1 x 10-2 atm of O2, what is the partial pressure of NO?
3. Given the following data at a certain temperature,
2N2(g) + O2(g) 2N2O(g) K = 1.2 x 10-35
N2O4(g) 2NO2(g) K = 4.6 x 10-3
½N2(g) + O2(g) NO2(g) K = 4.1 x 10-9
Calculate K for the reaction that produces one mole of dinitrogen monoxide gas and oxygen gas.
4. For the system, CO(g) + H2O(g) H2(g) + CO2(g), K = 1.30 at a certain temperature. If the partial pressure of CO and H2O is 0.355 atm and that for H2 and CO2 is 0.310 atm, what are the partial pressures of all four at equilibrium?
5. A solution of HBrC6H4COO acid is made by adding 1.750 x 10-2 moles of the acid in enough water to make a one liter solution. What would the hydronium ion concentration be at equilibrium? Ka = 1.00 x 10-4?
HBrC6H4COO(aq) + H2O(l) H3O(aq) + BrC6H4COO-(aq)
6.) What is the Ka value for HB, if a solution that is 0.45 M B- and 0.75 M HB produces a pH of 5.75? HB(aq) + H2O(l) H3O(aq) + B-(aq)
Explanation / Answer
Post multiple questions to get the remaining answers
CH4(g) + 2H2S(g) ------- CS2(g) + 4H2(g)
a) Kp = [H2]^4[CS2]/([CH4][H2S]^2)
=> 9.42
Reaction is not at equilibrium and will move towards left
b) Kp = [H2]^4[CS2]/([CH4][H2S]^2)
=> 1.775
Reaction is not at equilibrium and will move towards right
2)
Kp = [NO]^2/([N2][O2])
[NO]^2 = 0.0025 * 5.3 * 10^(-2) * 2.1 * 10^(-2)
[NO]^2 = 0.0000027825
[NO] = 0.001668 atm
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