In the following reaction, how many grams of silver iodide, Agl, will be produce
ID: 1007846 • Letter: I
Question
In the following reaction, how many grams of silver iodide, Agl, will be produced from 87.9 g of calcium iodide, Cal_2? CaI_2 + 2AgNO_3 rightarrow 2AgI + Ca(NO_3)_2 Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb(NO_3)_2 (aq) + 2NH_4I(aq) rightarrow PbI_2(s) + 2 NH_4NO_3(aq) What volume of a 0.550 M NH_4I solution Is required to react with 785 mL of a 0.100 M Pb(NO_3)_2 solution? How many moles of PbI_2 are formed from this reaction? The combustion of octane, C_6H_16, proceeds according to the reaction 2C_8H_18(l) + 25O_2(g) rightarrow 16CO_2(g) + 18H_2O(l) If 587 mol of octane combusts, what volume of carbon dioxide is produced at 28.0 degree C and 0.995 atm? An unknown substance has a mass of 20.7 g. The temperature of the substance increases by 14.3 degrees Celsius when 69.6 J of heat is added to the substance. What is the most likely identity of the substance? The table lists the specific heats of select substances. water aluminum iron silver lead copper Complete and balance the precipitation reaction. Include physical states in your answer. Click here for solubility rules. CuCl_2(aq) + Na_2CO_3(aq) If you combine 350.0 mL of water at 25.00 degree C and 130.0 mL of water at 95.00 degree C, what is the final temperature of the mixture? Use 1.00 g/mL as the density of water. Complete this table. Note that the atoms/ions are not necessarily neutral. Element: Mass number: Number of neutrons: Number of protons: Number of electrons: Charge: Which of the following measurements contain three significant figures? 0.001 0.00100 500 5.0 Times 10^2 1.00 Times 10^-3 395Explanation / Answer
1)
CaI2 + 2 AgNO3 ------> 2AgI + Ca(NO3)2
1 mole of CaI2 produces 2 moles of AgI2
294 g of CaI2 produces 2*234 g of AgI
87.9 g of CaI2 produces 2*234/294*87.9 g of AgI
= 139.92 g of AgI
2)
Pb(NO3)2 + 2 NH4I -----> PbI2 + 2NH4NO3
M1V1/n1 = M2V2/n2
0.1*785/1 = 0.55*V2/2
V2 = volume of NH4I solution = 284.454 mL
3)
2C8H18 + 25O2 ----> 16CO2 + 18H2O
2 moles of octane produces 16 moles of CO2
587 moles of octane produces 16*587/2 moles of CO2
= 4696 mol of CO2
Volume of CO2 = nRT/P = 4696 * 0.0821 * 301/0.995 = 116631.17 L
4)
q = m * s * dT
69.6 = 20.7 * s * (14.3)
s = 0.235
Answer : Silver
5)
CaCl2 (aq) + Na2CO3 (aq) ------> CaO(aq) + CO2(g) + 2NaCl(aq)
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