Label each of the following solutions as isotonic, hypotonic, or hypertonic (rel
ID: 1007943 • Letter: L
Question
Label each of the following solutions as isotonic, hypotonic, or hypertonic (relative to the cytosol of a typical red blood cell, which has a total concentration of 0.28 M) a. 0.14 M CaCl_2 b. 0.14 M urea (N_2H_2CO. a non electrolyte) C. 0.14 M NaHr d. A solution containing 0.03 M Na_2CO_2, 0.06 M KCI, and 0.07 M glucose (a nonelectrolyte) a. You have 5.00 mL of 1.60 M potassium bromide solution. If you add water until the total volume reaches 500.0 ml, what will be the molarity of potassium bromide in the resulting solution? b. You have 32.5 mu L of a 0.300% (w/v) fructose solution. If you add water until the total volume reaches 250 mu L, what will be the percent concentration of fructose in the resulting solution?Explanation / Answer
Ans 4 - a) Here, we use M1V1 = M2V2
M1 = Molarity of KBr, V1= Volume of KBr M2 = Molarity of resulting solution V2 = Volume of resulting
solution
M1 = 1.60 M, V1 = 5 ml or 0.005 L, M2 = ? , V2 = 0.500 L
M1 V1 = M2 V2
Now, 1.60 x 0.005 = M2 X 0.500
M2 = 0.016 M
b) M1 = Percent concentration of fructose solution, V1 = Volume of Fructose solution
M2 = Percent concentration of resulting solution, V2 = Volume of resulting solution
M1V1 = M2V2
M1 = 0.300 %. V1 = 32.5 microlitre, M2 = ? , V2 = 250 microlitre
0.300 x 32.5 = M2 x 250
M2 = 0.039 M
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