Please help solve questions 2,3, & 4 please! QUESTION 2 20 points save Answer Be

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Please help solve questions 2,3, & 4 please! QUESTION 2 20 points save Answer Benzene freezes at 5.5°c under 1 atm. The density of benzene changes from o879 g/cm in liquid form to 0.891 goma in solid form. Its enthalpy of fusion is 10.59 by 1000 atm, enter your answer with 1 decimal. For exa mple, 10.56 is written as 10.6. Hint: Find phase transition molar volume change (unit: msimo) using density and molar mass, together with the entropy change (AHT, and then use Clapeyron equation to calculate AT AP given. Refer homework 4 question 4. Please pay attention to the unit: kJ need to convert to J. 341.3 QUESTION 3 30 points save Answer Calculate vapor pressure of benzene at 25.5°C using Clausius-Clapeyron Equation. The normal boiling point of benzene is 80.1°C, and its molar heat of vaporization is 30,8kJWmol. Answer (in units of atm) with 2 decimals, such as 1.23 QUESTION 4 30 points save Answer chloroform, CHcls, has a vapor pressure of 197 mmHg at 23.0 C, and its heat of vaporization is 29.2kJWmol, Estimate the temperature at which its vapor pressure is 448 mmHg. Please enter your answer (unit in "C with one decimal, such as 29.2 (not Enotation).

Explanation / Answer

3) P1 = ? , T1 = 25.5 C = 298.65 k

   P2 = 1 atm T2 = 353.25 k

ln(p2/p1) = DHvap/R[1/T1-1/T2]

ln(1/x) = (30.8*10^3/8.314)((1/298.65)-(1/353.25))

x = vapor pressure at 25.5 c = 0.147 atm

4)

P1 = 197 mmhg , T1 = 23 C = 296.15 k

   P2 = 448 mmhg T2 = ?

ln(p2/p1) = DHvap/R[1/T1-1/T2]

ln(448/197) = (29.2*10^3/8.314)((1/296.15)-(1/T2))

x = temperature = 318.19 K = 45.04 c

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