Question 6 of 15 incorrect ncorrect Tutorial lesson Mapdan University Science Bo

Question

Question 6 of 15 incorrect ncorrect Tutorial lesson Mapdan University Science Books General Chemistry 4th Edition McQuarrie Rock Gallogly presented by Sapling Learning Cryolite, Na3AIF6(s), an ore used in the production of aluminum, can be synthesized using aluminum oxide. Tip: If you need to clear your Balance the equation. work and reset the equation, Alro, (s) 6NaoHI) 12HF(g) 2Na, AIF 9H,o(g) click the button that looks like two red arrows. If 11.00 kilograms of Al203(s), 52.4 kilograms of NaOH and 52.4 kilograms of HF(g) react completely, how many kilograms of cryolite will be produced? Number 45.30 kg Na Al Fe Which reactants will be in excess? What is the total mass of the excess reactants left over after the reaction is complete? AI203 Incorrect. Number For extra help, complete the tutorial NaOH kg above. Note: you don't lose any points for attempting a tutorial 44.06 HF A Previous Give Up & View Solution Try Again Next Exit

Explanation / Answer

Al2O3 + 6 NaOH + 12 HF 2 Na3AlF6 + 9 H2O

(11.0 kg Al2O3) / (101.9614 g Al2O3/mol) x (2/1) = 0.21576 kmol Na3AlF6

(52.4 kg NaOH) / (39.9971 g NaOH/mol) x (2/6) = 0.436698 kmol Na3AlF6

(52.4 kg HF) / (20.0064 g HF/mol) x (2/12) = 0.436527 kmol Na3AlF6

The reactant Al2O3 produces the least amount of product, Al2O3 is the limiting reactant. NaOH and HF are in excess.

(0.21576 kmol Na3AlF6 ) x (209.9413 g/mol) = 45.3 kg Na3AlF6 produced

(11.0 kg Al2O3) / (101.9614 g Al2O3/mol) x (6/1) x (39.9971 g NaOH/mol) = 25.89 kg NaOH reacted

(11.0 kg Al2O3) / (101.9614 g Al2O3/mol) x (12/1) x (20.0064 g HF/mol) = 25.90 kg HF reacted

(52.4 kg NaOH initially – 25.89 kg NaOH reacted) + (52.4 kg HF initially – 25.90 kg HF reacted) = 53.0 kg total excess reactants left over

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