Consider a 100 mol mixture that is 69.0% methane (CH4) and 31.0% ethane (C2H6).

Question

Consider a 100 mol mixture that is 69.0% methane (CH4) and 31.0% ethane (C2H6). To this mixture is added 25.0% excess air. Of the methane present, 94.40% reacts, 88.90% of which forms carbon dioxide (CO2), and the balance forms carbon monoxide (CO). Of the ethane present, 84.3% reacts, 88.90% of which forms carbon dioxide, and the balance forms carbon monoxide.

1) What is the theoretical amount of oxygen required for the fuel mixture?

2)What amount of air is added to the fuel mixture?

3)How many moles of methane are present in the product gas?

4)How many moles of ethane are present in the product gas?

5)How many moles of carbon dioxide are present in the product gas?

6)How many moles of carbon monoxide are present in the product gas?

7)How many moles of water vapor are present in the product gas?

8)How many moles of oxygen are present in the product gas?

9)How many moles of nitrogen are present in the product gas?

Explanation / Answer

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