Please show all of the work making it legible to read, it helps me learn the mat

Question

Please show all of the work making it legible to read, it helps me learn the material 1. Determine the pH of a solution that is 0.75 M benzoic acid, C&H; sCO,H, (K 6.4 x 10) and 0.50 M sodium benzoate. 2. Determine the pH of a buffer containing 2.0 M NH and 1.5 M NH 3. Determine the pH of 100.0mL of the solution in #1 to which 25.0 ml, of 0.20 M HNC) has been added. 4. A titration is performed on 100. mL of 0.10 M NaOH with 0.10 M HCI. a. What is the pH at the starting point of the titration? b. What volume of HCI solution is required to reach the equivalence point? c. What is the pH at the midpoint of the titration? d. What is the pH at the endpoint of titration? e. What would be the pH if an additional 10. mL of the HCl solution were added beyond the equivalence point? f Sketch the pH curve A titration is performed on5 NaOH. 5. What is the pH at the starting point? What volume of NaOH solution is required to reach the equivalence point? What would be the pH after every 10.0 mL of NaOH were added up to and including the equivalence point? What is the pH at the midpoint of the titration? Determine the pH after 10.0 additional mL of base has been added beyond the equivalence point. Sketch the pH curve (or graph using Excel, etc). Label the buffer zone, the midpoint, and the equivalence point a. b. c. d. e. f.

Explanation / Answer

1) pH = pKa + log(salt)/(acid)
pH = -log(6.4*10^-5) + log(0.5/0.75)
pH = 4.017
2) pOH = pKb + log(salt)/(base)
pOH = 4.75 + log (2/1.5)
pOH = 4.875
pH = 14 - 4.875 = 9.125
3) pH = pKa +log(salt - acid)/(acid + acid)
pH = 4.75 + log ((0.5*100/1000 - (25*0.2)/1000)/(0.75*100/1000 + (25*0.2)/1000))
pH = 4.5

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