Consider the Fisher projections of these two molecules. They would have: the dif
ID: 1010662 • Letter: C
Question
Consider the Fisher projections of these two molecules. They would have: the different melting points. different boiling points. equal but opposite optical rotations. More than one of the above. None of the above. These molecules are: constitutional isomers. Enantiomers. Diastereomers. Identical. none of the above. What can be said with certainty if a compound has [alpha]D^25 = +6.7 degree ? The compound is m a 10% solution. The compound has the (S) configuration. The compound has the (R) configuration. The compound is not a meso compound. The compound has an optical purity of less than 100%. Which of the following is a meso compound? (2R,3R)-2,3-Dibromobutane (2R,4S)-2,4-Dibfomopentane (2R,4R)-2,4-Dibromopentane (2R,3S)-2,3-Dibromopentane None of these Select the most likely rate law for the following reaction: (CH_3)_3C-Br + OH- rightarrow (CH_3)_3C-OH + Br- Rate = k [(CH_3)_3C-Br] Rate = k [(CH_3)_3C-Br] [OH-] Rate = k [(CH_3)_3C-Br] [OH-]^2 Rate = k [(CH_3)_3C-Br]^2 [OH-]^2 Rate = k [(CH_3)_3C-Br]^2 [OH-] Which of the following is an elimination reaction? CH-3CH_3 + Cl_2 rightarrow CH_3CH_2Cl + HCl CH_3CH_2Cl + OH^- Rightarrow CH_2 CH_2 + H_2O +Cl^- CH_3CH_2Cl + I^- Rightarrow CH_3CH_2I + Cl^- More than one of the above. None of the above.Explanation / Answer
17.
Answer is (b).
In elimination reaction elements are eliminated to give unsaturated compound.
Here alkyl halide form alkene.
16.
Answer is (a)
Its a tertiary halide. It will undergo SN1 reaction.
The only reactant that is undergoing change in the first (rate-determining formation of tertiary carbocation) step is the alkyl halide, so we expect such reactions would be unimolecular and follow a first-order rate equation.
15.
Answer is (b).
It has 2R and 4S configuration.
12.
Answer is (e).
Since both the structure are
(2S,3R)-2-bromo-3-chlorobutane.
Both are same molecule.
13.
Answer is (a)
Both the molecules have Chemical Formula: C6H12Br2. Constitutional isomers are compounds that have the same molecular formula and different connectivity.
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