For each of the following balanced chemical equations below, indicate how many a

Question

For each of the following balanced chemical equations below, indicate how many atoms of each element are present on the reactant (LHS) and product (RHS) sides of the chemical reaction. 2Cu + O_2 rightarrow 2 CuO LHS RHS 2H_2O rightarrow 2H_2 + O_2 LHS RHS BaCl_2 + Na_2S rightarrow BaS + 2NaCl LHS RHS 2C_3H_8O + 9O_2 rightarrow 8H_2O + 6CO_2 LHS RHS N_2 + 3H_2 rightarrow 2NH_3 LHS RHS 4Fe + 3O_2 rightarrow 2Fe_2O_3 LHS RHS Au_2S_3 + 3H_2 rightarrow 3H_2S + 2Au LHS RHS C_4H_10O + 6O_2 rightarrow 5H_2O + 4CO_2 LHS RHS

Explanation / Answer

Identify number of atoms on each side of reaction

9. 2Cu + O2 --> 2CuO  

LHS : Cu = 2 ; O = 2    RHS : Cu = 2 ; O = 2

10. 2H2O --> 2H2 + O2

LHS : H = 4 ; O = 2     RHS : H = 4 ; O = 2

11. BaCl2 + Na2S --> BaS + 2NaCl

LHS : Ba = 1 ; Cl = 2 ; Na = 2 ; S = 1     RHS : Ba = 1 ; Cl = 2 ; Na = 2 ; S = 1

12. 2C3H8O + 9O2 ---> 8H2O + 6CO2

LHS : C = 6 ; H = 16 ; O = 20         RHS : C = 6 ; H = 16 ; O = 20

13. N2 + 3H2 ---> 2NH3

LHS : N= 2 ; H = 6           RHS : N= 2 ; H = 6

14. 4Fe + 3O2 ---> 2Fe2O3

LHS : Fe = 4 ; O = 6          RHS : Fe = 4 ; O = 6

15. Au2S3 + 3H2 ---> 3H2S + 2Au

LHS : Au = 2 ; S = 3 ; H = 6       RHS : Au = 2 ; S = 3 ; H = 6

16. C4H10O + 6O2 ---> 5H2O + 4CO2

LHS : C = 4 ; H = 10 ; O = 13          RHS : C = 4 ; H = 10 ; O = 13

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