O 7/8/2016 11:45 PM A 74.8/100 7/8/2016 05:54 PM Gradebook Print Calculator L Pe

Question

O 7/8/2016 11:45 PM A 74.8/100 7/8/2016 05:54 PM Gradebook Print Calculator L Periodic Table Incorrect X Incorrect X Question 26 of 27 Incorrect a Sapling Learning macmillan learning A current of 5.39 A is passed through a Pb(NO3)2 solution. How long (in hours) would this current have to be applied to plate out 5.20 g of lead? Number 1.49 There is a hint available! View the hint by clicking on the bottom divider bar. Click on the divider bar again to hide the hint. Close Previous Give Up & View Solution Check Answer Next Exit Hint

Explanation / Answer

Pb^2+ + 2e Pb

w = Z* i* t/96500

molar mass of Pb(NO3)2 = 331.2 g/mol

5.2 = (331.2/2)(5.39)(3600*t)/96500

t= 0.15 h

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