Exercise 18.22 Decide whether or not each metal dissolves in 1 M HCl. For those

Question

Exercise 18.22

Decide whether or not each metal dissolves in 1 M HCl. For those metals that do dissolve, write a balanced redox reaction showing what happens when the metal dissolves.

Part A

Cu

Express your answer as a chemical equation. Enter noreaction if there is no reaction. Identify all of the phases in your answer.

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Part B

Co

Express your answer as a chemical equation. Enter noreaction if there is no reaction. Identify all of the phases in your answer.

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Part C

Na

Express your answer as a chemical equation. Enter noreaction if there is no reaction. Identify all of the phases in your answer.

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Exercise 18.22

Decide whether or not each metal dissolves in 1 M HCl. For those metals that do dissolve, write a balanced redox reaction showing what happens when the metal dissolves.

Part A

Cu

Express your answer as a chemical equation. Enter noreaction if there is no reaction. Identify all of the phases in your answer.

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Part B

Co

Express your answer as a chemical equation. Enter noreaction if there is no reaction. Identify all of the phases in your answer.

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Part C

Na

Express your answer as a chemical equation. Enter noreaction if there is no reaction. Identify all of the phases in your answer.

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Explanation / Answer

Solution:- (Part A) In activity series Cu is below hydrogen so it can't replace hydrogen gas from HCl and hence there would be no reaction.

(Part B) Co is above hydrogen in activity series and hence it would get dissolved in HCl and oxidized to Co+2 and the reaction is as follows...

Co(s) + 2HCl(aq) ---------> CoCl2(aq) + H2(g)

This reaction could also be written as....

Co(s) + 2H+(aq) ---------> Co+2(aq) + H2(g)

In this reaction Co is oxidized from 0 to +2 state and H is reduced from +1 to 0 state.

(Part C) Na is a highly reactive metal and releases hydrogen gas from hydrogen acids.

2Na(s) + 2HCl(aq) -------> 2NaCl(aq) + H2(g)

Or it could also be written as....

2Na(s) + 2H+(aq) --------> 2Na+(aq) + H2(g)

Na is oxidized from 0 to +1 state and H is reduced from +1 to 0 state.

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