Which statement is correct in mechanism of reduction of benzophenone by NaBH4 in
ID: 1011715 • Letter: W
Question
Which statement is correct in mechanism of reduction of benzophenone by NaBH4 in methanol: Hydride ion attacks carbonyl carbon (C=O) and pi bond breaks Hydride ion attacks carbonyl oxygen (C=O) and pi bond breaks H^+ attacks carbonyl carbon (C=O) and pi bond breaks H^+ attacks carbonyl oxygen (C=O) and pi bond breaks Based on Solubility data for benzophenone what is the best method to purify it by recrystallization: vs in hot methanol, vs in cold methanol, ss in hot and cold water vs (very soluble), s (soluble), ss (slightly soluble) Dissolve in hot methanol and let cool down to room temperature slowly then in ice bath overnight Dissolve in hot methanol, add water slowly until it gets cloudy let cool down to room temperature slowly Dissolve in hot water and cool down slowly then put in ice bath overnight All three methods work perfectly to purify benzophenone with high yield True or false: To get a better yield in reduction of benzophenone it's better to dissolve LiAIH_4; in H_2O and add very slowly to benzophenone solution. LiAIH_4 is stronger reducing agent and increases yield of reaction.Explanation / Answer
16. Answer is A
17.answer is C
18. Answer is true
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