Use the following information to answer questions 2 through 8: Diethyl ether, CH

Question

Use the following information to answer questions 2 through 8:

Diethyl ether, CH3CH2OCH2CH3 ,

specific heat solid:

1.89 J/g K

heat of fusion:

7.19 kJ/mol

normal melting point:

–116.3 °C

Molar mass:

74.1 g/mole

specific heat liquid:

2.32 J/g K

heat of vaporization:

27.2 kJ/mol

normal boiling point:

34.6 °C

specific heat gas:

1.61 J/g K

3.  What is the vapor pressure at 25°C?

specific heat solid:

1.89 J/g K

heat of fusion:

7.19 kJ/mol

normal melting point:

–116.3 °C

Molar mass:

74.1 g/mole

specific heat liquid:

2.32 J/g K

heat of vaporization:

27.2 kJ/mol

normal boiling point:

34.6 °C

specific heat gas:

1.61 J/g K

Explanation / Answer

At boiling point of a compound, vapour pressure of compound = atmospheric pressure = 1 atm.

For diethyl ether, boiling point = 34.6 oC

So, at T= 34.6 oC, vapour pressure of diethyl ether = 1 atm.

According to ideal gas equation, PV= nRT

So, P is directly proportional to T.

25 oC < 34.6 oC

So at 25 oC, vapour pressure of diethyl ether would be less than pressure observed at 34.6 oC.

Thus, it would be less than 1 atm.

1st option is correct.

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