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O 7/8/2016 11:45 PM A 74.8/100 O 7/8/2016 05:54 PM Gradebook Print Calculator L

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Question

O 7/8/2016 11:45 PM A 74.8/100 O 7/8/2016 05:54 PM Gradebook Print Calculator L Periodic Table Incorrect Incorrect Question 17 of 27 a Sapling Learning macmillan learning Calculate the standard free-energy change for the following reaction at 25 oC Standard reduction potentials can be found here. 2 Au 3 (aa) 3Nis .2+ Number AG 2061.24 kJ There is a hint available! View the hint by clicking on the bottom divider bar. Click on the divider bar again to hide the hint. Close Previous Give Up & View Solution Check Answer Next Exit Hint

Explanation / Answer

we know that

oxidation takes place at anode

and

reduction takes place at cathode

so

anode : oxidation

3Ni --> 3Ni+2 + 6e-

cathoode : reduction

2 Au+3 + 6e- --> 2 Au (s)

now

we know that

Eo cell = Eo cathode - Eo anode

Eo cell = Eo Au+3/Au - Eo Ni+2/Ni

Eo cell = 1.498 - (-0.26)

Eo cell = 1.758

now

we know that

dGo = -nFEo

here

n = 6 as six electrons are transferred

F = faradays constant = 96485

so

dGo = -6 x 96485 x 1.758

dGo = -1017724 J

dGo = -1017.724 x 1000 J

dGo = -1017.724 kJ