Choose ALL the correct products for the following reaction: NH 4 Cl( aq ) + Hg 2

Question

Choose ALL the correct products for the following reaction:

NH4Cl(aq)    + Hg2(C2H3O2)2(aq)   -->

a. Hg2Cl2(aq)    
b. Hg2Cl2(s)    
c. NH4C2H3O2(aq)
d. NH4C2H3O2(s)
e. NH4Hg2(aq)
f. NH4Hg2(s)
g. NH4(C2H3O2)2(aq)
h. NH4(C2H3O2)2(s)

[mark all correct answers]

Value: 1

Choose ALL the correct answers. What are the spector ions in the reaction:

NH4Cl(aq)    + Hg2(C2H3O2)2(aq)   -->

a. Hg22+(aq)
b. Hg+(aq)
c. NH4+(aq)
d. C2H3O2-(aq)
e. C2H3O22-(aq)
f. Cl-(aq)

[mark all correct answers]

Value: 1

What is the precipitate from the following reaction

NH4Cl(aq) + Hg2(C2H3O2)2(aq) -->

a. Hg2Cl2(aq)
b. Hg2Cl2(s)
c. NH4C2H3O2(aq)
d. NH4C2H3O2(s)
e. NH4Hg2(aq)
f. NH4Hg2(s)
g. NH4(C2H3O2)2(aq)
h. NH4(C2H3O2)2(s)

Explanation / Answer

2 NH4Cl (aq)    + Hg2 (C2H3O2)2(aq)     --------à Hg2Cl2(s) + 2 NH4C2H3O2(aq)

ALL the correct products for the reaction are b. Hg2Cl2(s) and c. NH4C2H3O2 (aq)( It is Double displacement reaction.)

The spectator ions in the reaction are c. NH4+ and d. C2H3O2-

(Spectator ions are present in the same form throughout the reaction.)

NH4 + +Cl-    + Hg2 + +(C2H3O2-)2 --------à Hg2Cl2(s) + NH4+ + C2H3O2-

The precipitate from the reaction is b. Hg2Cl2(s)

(When NH4Cl reacts with aq Hg2 (C2H3O2)2 yellowish-white precipitate of Hg2Cl2(s) is formed.)

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