The purification of hydrogen gas by diffusion through a palladium sheet was disc

Question

The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 6.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm- thick sheet of palladium having an area of 0.20 m^2 at 500 degree C. Assume a diffusion coefficient of 1.0 Times 10 m^2/s, that the respective concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained.

Explanation / Answer

thickness = 5mm = 5*10-3m

Flux= Diffusivity* concentration difference in moles/m3/thickness

= 1*10-8*(2.4-0.6)/5*10-3 = 3.6*10-6 kg/m2.s

Area of palladium = 0.2m2

hydorgene passing through palladium = 0.0000036*0.2 = 7.2*10-7 kg/s

so 1 second, 7.2*10-7 kg of hydrogen passes through

in 3600 sec ( 1hr= 60minutes= 60*60 seconds) , hydorgen = 7.2*10-7*3600 kg/hr=0.00259 kg/hr

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