In this experiment, you will prepare 5 solutions. Four solutions will contain a

Question

In this experiment, you will prepare 5 solutions. Four solutions will contain a mixture of AgNO and CH,COONa. The fifth solution will contain pure AgNO, AgNO, and CH,COONa will reac according to the following reaction: 00Na will react Some of the solid will dissociate in water according to the following equation You will discard the solid that did not dissociate (it remained as a precipitate) as well as AgNO CH,COONa, and NaNO, You will then determine the amount of Ag' present in the solution by titrating it with KSCN. The following reaction will take place: Ag·W" SCN, tau AgSCN lsi (white precipitate) When the orange color of ferric alum indicator becomes visible, all of Ag' has precipitated out and the SCN is now reacting with the Fe the number of moles of Ag' is equivalent to the number of moles of SCN at this point). OBJECTIVE Calculate the solubility product (K) of silver acetate. PROCEDURE 1. Calculate the required mass of AgNO, to prepare a 100 ml solution with a concentration 2. Prepare the 0.2 M solution of AgNO, with the 100.00 mL volumetric flask. 3. Calculate the actual concentration of the AgNO, solution. Show the calculation 4. Calculate the required mass of CH,COONa-3H,0 required to prepare a 100 mL solution of 5. Prepare the 0.2 M solution of CH,COONa wi 6. Calculate the actual concentration of the CH,COONa solution. Show th of 0.2 M. Show the calculation in the report fo Record the t form report form CH,COONa, 0.2 M. Show the calculation in the report form. th the 100.00 mL volumetric flask. Record the report form

Explanation / Answer

Final [CH3COOAg] = Final [AgNO3] = moles of KSCN/Total volume

moles of KSCN = molarity of KSCN/total volume of solution

Final [CH3COONa] = initial [CH3COONa] - Final [CH3COOAg]

1 mole of CH3COONa reacts with 1 mole of AgNO3 to form 1 mole of CH3COOAg and 1 mole of NaNO3

Lowest mole of the two would be the limiting reagent

1 mole of Ag+ reacts with 1 mole of SCN- to form 1 mole of AgSCN

moles of Ag+ reacted = moles of CH3COOAg in solution

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Table                                #1(mM)          #2(mM)            #3(mM)             #4(mM)

Initial AgNO3                       60                   100                 120                     140

Initial [CH3COONa]            140                  100                   80                       60  

Initial [CH3COOAg]            1.71                 2.86                 2.28                    1.71

Initial [NaNO3]                    1.71                 2.86                 2.28                    1.71

Final [AgNO3]                       -                       -                     1.14                    2.28

Final [CH3COONa]            0.114              1.68                      -                          -

Final [CH3COOAg]             1.68                2.83                  2.24                    1.67

Final [NaNO3]                     1.71                 2.86                 2.28                    1.71

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