The reaction of the strong acid HCI with the weak base CH_3NH_2 is: HCl(aq) + CH

Question

The reaction of the strong acid HCI with the weak base CH_3NH_2 is: HCl(aq) + CH_3NH_2(aq) rightarrow CH_3NH^+_3(aq) + Cl^-([aq) To compute the pH of the resulting solution if 35mL of 0.35M acid is mixed with 57mL of 0.57M base we need to start with the stoichiometry. Let's do the stoich in steps: How many moles of acid? What is the limiting reactant? How many moles of base? How many moles of the excess reagent after reaction? What is the concentration of the excess reagent after reaction? What is the concentration of the pH active product after reaction?

Explanation / Answer

HCl + CH3NH2 CH3NH3+ + Cl-

Initial Amount of Reactants

Reactants

Initial Amount

mole

gram

HCl

12.25

446.6105

CH3NH2

32.49

1009.07442

Unreacted Amount of Reactants

Reactants

Final Amount

mole

gram

HCl

0

0

CH3NH2

20.24

628.61392

Amount of Products Produced

Products

Final Amount

mole

gram

CH3NH3

12.25

392.8085

Cl

12.25

434.2625

The limiting reactant is the reactant that limits the amount of product that can be formed and is completely consumed during the reaction. Hence HCl is the limiting reagent.

Reactants

Initial Amount

mole

gram

HCl

12.25

446.6105

CH3NH2

32.49

1009.07442

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