Half-fife for first-order reactions: where t\\/2 is the half-life in seconds (s)
ID: 1015957 • Letter: H
Question
Half-fife for first-order reactions: where t/2 is the half-life in seconds (s). and k is the rate constant in inverse seconds (s^-1). What is the half-fife of a first-order reaction with a rate constant of 5.80 times 10-Express your answer with the appropriate units. What is the rate constant of a first-order reaction that takes 384 seconds for the reactant concentration to drop to half of its initial value? Express your answer with the appropriate units. A certain first-order reaction has a rate constant of 4.30 times 10 s. How long will it take for the reactant concentration to drop to 1/8 of its initial value? Express your answer with the appropriate units.Explanation / Answer
What is the Half life of first order reactions with rate constant of 5.80 x10^-4
a) t 1/2 = 0.693 / 5.80 x 10^-4 = 1194.8 seconds
========================
b) = t = 384= 384 s
ln 0.5 = - k x 384
k = - 1.80 x 10^-3
========================
1/8=0.125
===================
c) ln 0.125 = - 4.30 x 10^-3 t
ln 0.125/ - 4.30 x 10^-3 =0.0004835910
t = 483.6 seconds-answer
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.