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Gradebook | | Assignm Celculutr Periocic Tuble al Available F Due Date: Points P

ID: 1016238 • Letter: G

Question

Gradebook | | Assignm Celculutr Periocic Tuble al Available F Due Date: Points Poss Grade Cate Description Policies: Sapling Learning At a certain temperature, the K for the decompositon of H2S is 0773. Initally, only H-S is present at a pressure of 0.248 bar in a dlosed container. What is the total pressure in the container at equilibrium? You can check You can view assignment You have two There is no per Number bar O eTextbook O Help With T Web Help & O Technical S O Previous @check Answer @wxtxit A Check Answer 0 Next Exit Hint

Explanation / Answer

from the given data

KP = pH2*pS/pH2S

0.773 = X^2/(0.248-X)

X = 0.197 bar

at equilibrium

partial pressure of H2 = pH2 = 0.197 bar

partial pressure of S = pS = 0.197 bar

partial pressure of H2s = pH2s = 0.248-0.197 = 0.051 bar

total pressure at equilibrium = pH2+pS+pH2S

   = 0.197+0.197+0.051

   = 0.445 bar

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