3.Rank the following quantities in order of decreasing distance. Rank from highe
ID: 1016554 • Letter: 3
Question
3.Rank the following quantities in order of decreasing distance.
Rank from highest to lowest distance. To rank items as equivalent, overlap them.
1 km -->100 m-->1 cm-->1 Mm-->50 mm-->1 mm-->5 million nm
8. a).What will be the amount of sugar in milligrams if the size of the milk chocolate bar is reduced from 14.630 g to 5.000 g? Express your answer in milligrams to four significant figures.
b).Given that a 14.630 g milk chocolate bar contains 9.315 g of sugar, calculate the percentage of sugar present in 14.630 g of milk chocolate bar keeping in mind that the answer should have four significant figures (two decimal places).Express your answer numerically to four significant figures.
10. a).You need 4.1 ounces of a steroid ointment. If there are 16 oz in 1 lb, how many grams of ointment does the pharmacist need to prepare?Express your answer using two significant figures.
D).Blueberry high-fiber muffins contain 51 % dietary fiber. If a package with a net weight of 16 oz contains six muffins, how many grams of fiber are in each muffin?Express your answer using two significant figures.
Explanation / Answer
3. 1 km -->100 m-->1 cm-->1 Mm-->50 mm-->1 mm-->5 million nm
Convert all these into m = 1000 m, 100 m, 0.01 m, 106 m, 50*10-3 m, 10-3 m, 0.005 m
1 Mm > 1 km > 100 m > 50 mm > 1 cm > 5 million nm > 1 mm
8. a) I will take the value of sugar in chocolate bar from part b.
14.630 g milk chocolate bar contains sugar = 9.315 g
5.000 g milk chocolate bar contains sugar = (9.315/14.630)*5.000 = 3.184 g = 3184 mg
b) Mass of sugar = 9.315 g
Mass of chocolate bar = 14.630 g
% of sugar in bar = (mass of sugar/mass of chocolate)*100 = (9.315/14.630)*100 = 63.67 %
10. a) 4.1 ounces = 4.1 oz
16 oz = 1 lb
So, 4.1 oz = 4.1/16 = 0.256 lb
1 lb = 453.6 g
So, 0.256 lb = 453.6*0.256 = 116.24 g = 120 g
D. A package of 6 muffins = 16 oz
one muffin = 16/6 = 2.67 oz
1 oz = 28.35 g
So, 2.67 oz = 28.35*2.67 = 75.69 g
Dietery fiber = 51 % of 75.69 g = (51/100)*75.69 = 38.60 % = 39 %
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