need some help with balancing the cathode and anode A galvanic cell is powered b

Question

need some help with balancing the cathode and anode

A galvanic cell is powered by the following redox reaction 4 Cu2+(aq) + N2H4(aa) + 4 OH-(aq) 4 Cu.(aq) + N2(g) + 4 H 20() Answer the following questions about this cell. If you need any electrochemical data, be sure you get it from the ALEKS Data tab Wrhe a balanced equation for the half-reaction that takes place at the halt-reaction that takes place at the wime a balaneed equation for tho half-reaction that takea place at the place at the Calculate the cell voitage under Round your answer to 2 decimal places

Explanation / Answer

at cathode reduction takes place and therefore the half reaction is

Cu2+ + e- ---------------------> Cu+

at anode oxidation takes place and the half reaction is

N2H4 + 4OH- --------------------> N2 + 4H2O + 4e-

E0 = + 0.153 V + 1.160 V

= + 1.313 V

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