write a rate law for this reaction and calculate the value of the rate constant
ID: 1019137 • Letter: W
Question
write a rate law for this reaction and calculate the value of the rate constant k with correct unit symbols
Some measurements of the initial rate of a certain reaction are given in the table below. N2 H2 initial rate of reaction 1.54M 1.28 M 5.00 x 105 MIS 2.14 M 1.28M 6.95 x 103 M/S s 1.54 M 3.56 M 3.87 x 106 MIs Use this information to write a rate law for this reaction, and calculate the value of the rate constant k. Round your value for the rate constant to 2 significant digits. Also be sure your answer has the correct unit symbolExplanation / Answer
The rate of a chemical reaction is the amount of substance reacted or produced per unit time. The rate law is an expression indicating how the rate depends on the concentrations of the reactants and catalysts. The power of the concentration in the rate law expression is called the order with respect to the reactant or catalyst
Hence let us find out order of the reaction
When we divide the second rate / first rate
2.14 x 1.28 / 1.54 x 1.28 = 6.95 x 105 / 5 x 105
[1.38] N2= [1.38]
Order of reaction according to N2 is one
The same way if we do third reaction divide first reaction
3.56 x 1.54 / 1.54 x 1.28 = 3.87 x 106 / 5 x 105
[2.78] H2= [7.74]
[2.78] H2= [2.78]2
Order of reaction according to H2 is two
Hence we can write rate law
R = k [N2] [H2]2
We can calculate rate constant value
5 x 105 =k [1.54] [1.28]2
k = 1.98 x 105 S M-2
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