Calculate the Eocell for: Zn(s) + Br2(g) Br-(aq) + Zn2+(aq) ; is this electrolyt

Question

Calculate the Eocell for: Zn(s) + Br2(g) Br-(aq) + Zn2+(aq) ; is this electrolytic or voltaic?

When a solid piece of copper is placed in a solution of SnCl2 will a reaction occur?

The balanced overall equation for: Au3+(aq) + Br-(aq) Au(s) + Br2(g)

Calculate the Eocell of: Au(s) ; Au3+(aq) || Mn2+(aq) ; Mn(s)    is this electrolytic or voltaic?

How many faradays is needed to "plate out" 100.0 g of chromium?

Calculate the Ecell of: Al(s) + Sn2+(aq)(0.010M) Al3+(aq)(1.0M) + Sn(s) (is this balanced?)

Explanation / Answer

Zn(s) + Br2(g) Br-(aq) + Zn2+(aq)
Zn (s) ----> Zn+2 (aq) oxidation reaction so it is anode
Br2 (g) -----> 2Br- (aq) reduction reaction so it is cathode
E0 cell = E cathode - E anode
E0 cell = 1.09 - (0.76) = 1.85 V
Sn+2 + 2e- ---> Sn ; E0 = -0.14
Cu+2 + 2e- ---> Cu ; E0 = +0.34
Hence E0 value of Cu is high compare to SN+2 so it cannot replace the sn+2 in the solution.
Au3+(aq) + Br-(aq) Au(s) + Br2(g)
Au+3 -----> Au (reduction by 3 e-)
Br- -----> Br2 (oxidation by 2 e-)
so the balanced equation is,
2Au+3 (aq) + 3 Br- (aq) -----> 3 Au (s) + 6 Br2 (g)
Au(s) ; Au3+(aq) || Mn2+(aq) ; Mn(s) is an galvonic cell because Au under goes oxidation and Mn+2 under goes reduction.
transfer of electrons takes place and deposition of metal takes place.

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