What is the conjugate base of HSO^-_4 in the reaction below? CO^2-_3 + HSO^-_4 H

Question

What is the conjugate base of HSO^-_4 in the reaction below? CO^2-_3 + HSO^-_4 HCO_3^- + SO^2-_4 CO^2-_3 SO_4^2- OH^- H_3O^+ HSO^-_4 Calculate the pH of a 0.021 M NaCN solution. [K_3(HCN) = 4.9 times 10^-10] Predict the direction in which the equilibrium will lie for the reaction H_2CO_3 + F^- HCO_3^- + HF; K_a_1(H_2CO_3) = 4.2 times 10^-7; K_a(HF) = 7.1 times 10^-4 to the left at equilibrium to the right A solution is prepared by adding 0.10 mol of sodium fluoride. NaF, to 1.00 L of water. Which about the solution is correct? The concentration of fluoride ions will be greater than the concentration of sodium ions. The solution is neutral. The concentrations of fluoride ions and sodium ions will be identical. The solution is acidic. The solution is basic. What is the [OH^-] for a solution at 25 degree C that has |H_3O^+] = 8.23 times 10^-2 M?

Explanation / Answer

5)

Conjugate base is formed from acid after removing H+

HSO4- after removing H+ gives SO42-

Answer: b SO4 2-

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