What is the freezing point of a 0.20 m solution of glucose. C_6H_12O_6, in water

Question

What is the freezing point of a 0.20 m solution of glucose. C_6H_12O_6, in water? (K_f for water is 1.858 degree C/m.) 0.37 degree C 0.19 degree C -0.19 degree C -0.37 degree C -0.74 degree C What is the boiling-point change for a solution containing 0.457 mol of naphthalene (a nonvolatile, nonionizing compound) in 250. g of liquid benzene? (K_b = 2.53 degree C/m for benzene) 4.62 degree C 1.38 degree C 5.54 degree C 1.156 degree C 0.289 degree C A solution consisting of 0.250 mol of methylbenzene, C_6H_5CH_3, in 246 g of nitrobenzene. C_6H_5NO_2, freezes at -1.1 degree C. Pure nitrobenzene freezes at 6.0 degree C. What is the freezing-point depression constant of nitrobenzene? 4.5 degreeC/m 3.5 degree C/m 28 degree C/m 7.0 degree C/m 14.0 degree C/m When a 17.1-g sample of an unknown compound is dissolved in 500. g of benzene, the freezing point of the resulting solution is 3.77 degree C. The freezing point of pure benzene is 5.48 degree C, and K_f for benzene is 5.12 degree C/m. Calculate the molar mass of the unknown compound. 51.2 g mol 10.0 g/mol 88g/mol 205 g/mol 102. g/mol Determine the osmotic pressure of a solution that contains 0.025 g of a hydrocarbon solute (molar mass = 340 g/mol) dissolved in benzene to make a 350-mL solution. The temperature is 20.0 degree C. 0.26 torr 1.3torr 1.7torr 3.8torr 3.6 torr Calculate the molecular weight of a small protein if a 0.27-g sample dissolved in 112 mL of water has an osmotic pressure of 9.7 mmHg at 24 degree C. (R = 0.0821 L atm(K mol)) 6.1 times 10^-3 g/mol 4.6 times 10^3 g/mol 1.7 times 10^2 g/mol 3.7 times 10^2 g/mol 6.1 g/mol The volume of a sample of gas measured at 45.0 degree C and 1.00 atm pressure is 4.00 L. What must the final temperature be in order for the gas to have a final volume of 5.00 L at 1.00 atm pressure? -18.6 degree C 36.0 degree C 56.3 degree C 124.5 degree C -216.8 degree C

Explanation / Answer

What is the freezing point of a 0.20 m solution of glucose, C6H12O6, in water. (Kf for water = 1.858°C/molal.

glucose has a vant hoff "i" factor of 1 because it is not ionic.

0.20 m x 1 x 1.858 = 0.371 degrees.

=-0.371

Option D----------ANSWER

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What is the boiling-point change for a solution containing 0.457 mol of naphthalene

What is the boiling point change for a solution containing a 0.457 moles of napthalene (a nonvolatile compound) in 250.g of liquid benzene? (Kb=2.53*C/molal for benzene)

= 0.457 moles / 0.250 g=1.828 m

Tb= Kb × m

= Tb= 2.53 × 1.828 =4.62 C

Option A----------ANSWER

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QUESTION 71:

M=0.250 mol/0.244kg

Delta Tf= m x kf

Kf = Delta Tf =7.2 C –ANSWER

OPTION D--ANSWER

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