Answer any of the questions that you can. EXAM 2 The 1.14 per liter. What is the

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Answer any of the questions that you can.

EXAM 2 The 1.14 per liter. What is the solubility of Caso in pure water at o oc is grams value of the solubility product of Caso 2 How many moles of Ca(NO,), must be added to I o L of a o.182 M KF solution to begin of CaF For CaF,. Ksp 4.0 x 10 3 The concentration of Mg seawater is 0.052 M. At what pH will 99% of the Mga be the in 89 x 10 Calculate the molar concentration of uncomplexed zn in a solution that contains 4 0.20 mole of zn(NH, per liter. The overall Kr for zn(NH, is 3.8 x 10 5 Assume that the enthalpy of fusion of ice i 6020 J/mol and does not vary is appreciably over the temperature range K. If one mole of ice at 0°C by heat supplied from surroundings at 276 K.what is the entropy change in the surroundings, in J/K? atm, if one mole of this substance is vaporized at 1 atm, calculate AG 7 The following questions refer to the following reaction at constant 25°Cand 1 atm. 789 kJ/mol. 2Fe(OH) (s) AH 2Fe(s) (3/2)O2(g) 3H2O(l) O2(g) Fe (OH)3(s) Fe(s) Substances 205 07 Determine AS Asuniv, and AG for the reaction (in kJ/mol K) 8 The standard free energy of formation of KCI(s) is -408.8 kulmol. Calculate AG for the reaction 2KC (s) 2K(s)+ Cl2(g). for the reaction H2(g) l2(g) 2HI 9 At 699 K, AG for this reaction if the reagents are both supplied at 10.0 atm pressure and the product is at 1.76 atm pressure. Given that AGro for NH 16.668 kJ/mol, calculate the equilibrium constant fo Nm (g) 3H2(g) 2 NH3(g) the following reaction at 298 K Consider the reaction: 2SO2(g) 2SO (g) for which AH 187.1 JIK at 25°C. Assuming that AH a AS are independent of temperature, calculate the temperature where Kp

Explanation / Answer

You stated that "Answer any of the questions that you can."

I am answering question No: 8

From the standard Thermodynamic values adopted from

https://sites.google.com/site/chempendix/thermo?pli=1

it is clear that Standard free energy of formation for elements is zero

i.e., Gf° K(s) = 0 kJ/mol and Gf° Cl2(g) = 0 kJ/mol

According to definition G° = Gf°(Products) - Gf°(Reactants)

G° = [(2*0)+0] - (2*-408.8 kJ/mol)

G° = +817.6 kJ/mol

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