A reaction that is spontaneous as written has an equilibrium position that lies

Question

A reaction that is spontaneous as written has an equilibrium position that lies far to the left is very rapid will proceed without outside intervention is also spontaneous in the reverse direction is very slow Calculate delta S degree_rxn for the following reaction. The S degree for each species is shown below the C_2 H_2(g)+ H_2(g) rightarrow C_2 H_4(g) S degree (J/mol-K) 200.9 130.7 219.3 112.3 J/K +550.9 J/K -550.9 J/K +337.1 J/K For a given reaction, delta H = -24.2 kJ/mol and delta_S = -55.5 J/K-mol. The reaction will have delta G = 0 at K. Assume that delta H and delta S do not vary with temperature. 0.436 2293 298 2.29 Identify the compound with the highest delta G degree_f. Cl_2(g) N_2(g) H_2(g) O_2(g) All compounds have a value of zero.

Explanation / Answer

13. C) will proceed without outside intervention . ( any external driving force is not required)

14. C2H2(g) + H2(g) -----> C2H4(g)

DSrxn = 219.3 - (200.9+130.7)

= -112.3 j/K

15. DG = DH-TDS

0 = (-24.2*10^3) - (x*(-55.5))

x =T = temperature = 436.04 k

16. as all are standard form

answer: E

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