ll. Problems (points as indicated) Partial credit is possible, but only if you s
ID: 1021646 • Letter: L
Question
ll. Problems (points as indicated) Partial credit is possible, but only if you show your work! (Watch your significant figures.) 23. points) Use the s information provided to calculate AS nn for the following reaction 4 NH3 (g) 5 or (g) 4 No (g 6H20 (g) +210.8 +188.8 N/(mol K)] +192.8 +205.2 24. (7 points) use the given reactions with their provided AG nn nformation to calculate AG for the following reaction: NO (g) O (g) NO2 (g) AG non +489.6 203 (g) 302 (g) Given: O2 (g) 20 (g) AG non +463.4. NO (g) oa (g) NO2 (g) O2 (g) AG. 199.5 kJExplanation / Answer
dSo = So product - So reactant
dSo = [ 4x210.8 + 6x188.8] - [5x205.2 + 4x192.8]
dSo = [843.2 + 1132.8] - [1026 + 771.2]
dSo = [1976] - [1797.2]
dSo = 178.8 J/mol K
24)
NO + O3 -----> NO2 + O2 = -199.5 kJ
O ----> 1/2 O2 = (-463.4 / 2) kJ ( reaction reversed and divided by 2)
(+) both reaction
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NO + O3 + O -------> NO2 + 3/2 O2 = -431.2 kJ
(-) O3 -------> 3/2 O2 = (489.6 /2) kJ ( reaction one divded by 2)
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NO + O ---------> NO2 = -186.4 kJ dGrxn
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