The equilibrium constant, K_p, has a value of 7.5 times 10^-4 at 22 K for the re

Question

The equilibrium constant, K_p, has a value of 7.5 times 10^-4 at 22 K for the reaction monoxide with chlorine. 2NO(g) + CL_2(g) doubleheadarrow 2NOCL(g) What is the value of K_c? 4.12E-5 7.50E-4 1.37F-2 1.38E0 7.32E1 A mixture 0.35X mole of carbon monoxide and 0.448 mole of bromine was placed into a rigid 1.00-L container and the system was allowed to come to equilibrium. The equilibrium concentration of COBr_2 was 0.318 M. What is the value of K_c for this reaction? CO(g) + Br_2(g) doubleheadarrow COBr_2(g) 5.04E-1 1.63E-2 6.15E-1 6.12E1 1.98E0 For the reaction PCl_3(g) + Cl_2(g) doubleheadarrow PCl_5(g) at a particular temperature. K_c = 32 4. Suppose a system at that temperature is prepared with: [PCl_5] = 0.63 M, [Cl_2] 0.53 M. and (PCl_3) = 0.23 M Which of the following is correct? The reaction will proceed in the direction of forming more PCl_5 until equilibrium is reached. The reaction is at equilibrium. None of these choices is correct. The reaction will proceed in the direction of forming more PCl_5 and Cl_2 until equilibrium is reached. The reaction will proceed in the direction of forming more PCl_3 and Cl_2 until equilibrium is reached. Find the pH of a 0.609 M aqueous solution of hypobromous acid (HOBr). for which k_a = 2.06 times 10^-9 5.10 0.22 4.45 8.90 10.25

Explanation / Answer

(13)

The relation between Kp and Kc is ,

Kc= Kp x (RT)delta n

Here delta n = number of moles of products - number of mole sof recatants.

=2-3

= -1

So, Kc = 7.5 x 10-4 x (0.082 atm L / mol K x 222 K )-1

= 4.12 x 10-5

option-(A) is the answer

(14)

Equilibrium cocn of COBr2 =0.318 M

Equilibrium cocn of CO will be = 0.358 M - 0.318 M

= 0.040 M

Equilibrium conc of Br2 = 0.448 M - 0.318 M

= 0.130 M

So, here Kc = (COBr2) / (CO) x(Br2)

= 0.318 M / 0.130 M x 0.040 M

= 61.2

= 6.12 E1

So, correct answer is (D)

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