e Dining CHM post out 1202-01 Lecture Entertainment 2016 Homework 10 Fall Family
ID: 1022949 • Letter: E
Question
e Dining CHM post out 1202-01 Lecture Entertainment 2016 Homework 10 Fall Family & M t McMur Chapter Google for & Relations may t Robinson Chrome Games & You News Recreation A want reference Problem Chemistry assignmentproblemID & At Part to iew? feedback 10.96 Tee (G feedback Events the 300.383 67393958 & Express temperature Section 7 nancy P degrees while & in completing xenon his colsius atoms problem to two the significant same Incorrect: Mi digits. average that Try Answers speed 4 Give Chmolecules Again: attempts have 46"C? a remaining At what temperature (C) will xenon atoms have the same average speed that ci2Explanation / Answer
average speed = (8RT/M)
here;
R = gas constant = 8.314 J/K/mole
T = temperature = 46 + 273 = 319 K
pi = 22/7 or 3.14
M = molecular mass of chlorine = 71 g = 0.071 k.g.
now calculate the average spped of Cl2 at 46 degree C
average speed = (8RT/M)
average speed = (8*8.314 *319*/3.14*0.071)
average speed = [ 21217.328/0.223 ]
average speed = [95144.97]
average speed = 308.5 m/ s
now we determine the temperature for Xe will have an average speed of 308.5 m/s of Cl2 molecule:
so molecular mass of Xe = 131.3 g = 0.1313 k.g.
average speed = (8RT/M)
here average speed = 308.5
R = 8.314 J/K/mole
T = ?
M = 0.1313 k.g.
308.5 = [ ( 8 X 8.314 X T) / (3.14 X 0.1313) ]
308.5 = [ (66.512 X T) / 0.4122 ]
308.5 = [ 161.359 X T ]
squaring both sides in order to remove square..
95172.25 = 161.359 X T
T = 91264.41/161.359
= 589.82K
= 316.82 degree C
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