The following equation is given: V= [(Pxa)/(P+b)(1- (1/ exp(-k1(P=k2Po)))] where

Question

The following equation is given: V= [(Pxa)/(P+b)(1- (1/ exp(-k1(P=k2Po)))] where V is velocity P is applied force and Po is measured force. the model has four constant parameters a,b,k1 and k2. If M is used to represent dimensions of mass, t for dimension of time and L for dimension of length, then choose the correct option below: - a is dimensionless -a has dimensions of t/L - a has dimensions of ML/t^2 -a has dimensions of t^2/(ML) 1 a has dimensions of L/t -k2 is dimensionless -k2 has dimensions of L/t -k2 has dimensions of t/L -k2 has dimensions of ML/t^2 -k2 has dimensions of t^2/(ML)

Explanation / Answer

The exponential part of the given equation is not clear. Is it exp(-k1(P-K2P0))?

However, the approach would be to use the folllowing dimensions:

1) Velocity = distance/time = L/t

2) Force, P and P0 will have the same dimensions: F = m* a = kg* m/s2 = ML/t2

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