A gas, behaving ideally, has a pressure P_1 and at a volume V_1. The pressure of

Question

A gas, behaving ideally, has a pressure P_1 and at a volume V_1. The pressure of the gas is changed to P_2. Using Avogadro's, Charles', or Boyle's law, develop an expression that would solve for the new volume V_2. P_1T_1 = P_2T_2 P_1/T_1 = P_2/T_2 V_1/T_1 = V_2/T_2 P_1 V_1 = P_2 V_2 A gas. behaving ideally, fills a fixed volume container at a pressure P_1 and at a temperature T_1. The temperature of the container to changed to T_2. Using Avogadro's. Charles', or Boyle's law, develop an expression that would solve for the new pressure P_2. P_1/T_1 = P_2/T_2 V_1/T_1 = V_2/T_2 P_1 V_1 = P_2 V_2 P_1 T_1 = P_2 T_2

Explanation / Answer

A) If we assume that the number of moles and temperature remains constant then according to Boyle's law

Pressure is inversely proportional to volume

so P = nRT/ V = K/V   [K = constant]

Or P1 = K/V1   and P2= K/V2

equation the two

K = P1V1 = P2V2 [Answer]

B) the volume is fixed, the moles are constant

P = nRT /V = K X T [K = constant]

So P1 = K1T1 and P2=KT2

Or P1/T1 = P2/T2 = constant [ answer]

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