At high temperatures phosphine (PH_3) dissociates into phosphorous and hydrogen

Question

At high temperatures phosphine (PH_3) dissociates into phosphorous and hydrogen by the following reaction: 4PH_3 rightarrow P_4 + 6 H_2 At 800 degree C the rate at which phosphine dissociate is 4.0x10^-6 C_PH_3 mol/L-S .The reaction occurs in a constant volume 10-L vessel and the initial concentration of phosphine is 5 mol/L. If 5 mol of the phosphine reacts, how much phosphorous and hydrogen is produced? Develop expressions for the number of moles of phosphine, phosphorous, and hydrogen present at any time, and determine how many hours it would take to produce 3 mol of P_4.

Explanation / Answer

a) From the balance equation it is seen that 4 mole phosphine produces 1 mole phosphorus and 6 mole hydrogen. So, 5 mole phosphine will produce, 1.25 mole phosphorus and 7.5 mole hydrogen.

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