Yeast is used to produce a direct-energy-coupled extracellular product (P) using
ID: 1024782 • Letter: Y
Question
Yeast is used to produce a direct-energy-coupled extracellular product (P) using glucose as the carbon source that can be described by the following chemical equation. 1.14 moles of CO2 and 2.6 moles of water are produced per mole of glucose consumed.
C6H12O6 + b NH3 + a O2 —> c CH1.8O0.5N0.2 (biomass) + d C3H6O3 (P) + e H2O + f CO2
What is the yield of biomass from substrate (YXS) in molar units?
Stoichiometry. Yeast is used to produce a direct-energy-coupled extracellular product (P) using glucose as the carbon source that can be described by the following chemical equation. 1.14 moles of CO2 and 2.6 moles of water are produced per mole of glucose consumed. 12 b NH3 a O2 c CH18 oo.5No.2 (biomass) +d C3H603 (P) e H20+ f CO What is the yield of biomass from substrate (Yxs) n molar units?Explanation / Answer
consider the unbalanced reaction
C6H12O6 + b NH3 + a O2 —> c CH1.8O0.5N0.2 (biomass) + d C3H6O3 (P) + e H2O + f CO2
given
1.14 moles of C02 and 2.6 moles of water are produced
so
f = 1.14
e = 2.6
the reaction becomes
C6H12O6 + b NH3 + a O2 —> c CH1.8O0.5N0.2 (biomass) + d C3H6O3 (P) + 2.6 H2O + 1.14 CO2
now
using conservation principle
number of C atoms in reactants = number of C atoms in products
1 x 6 = ( c x 1) + ( d x 3) + 1.14
6 = c + 3d + 1.14
c + 3d = 4.86
now
number of N atoms in reactants = number of N atoms in products
b = c x 0.2
c = 5b
now
number of H atoms in reactants = number of H atoms in products
so
1 x 12 + ( b x 3) = ( c x 1.8) + ( d x 6) + ( 2.6 x 2)
12 + 3b = 1.8c + 6d + 5.2
6.8 + 3b = 1.8c + 6d
now
b = 0.2 c
so
6.8 + ( 3 x 0.2c) = 1.8c + 6d
6.8 + 0.6c = 1.8c + 6d
1.2c + 6d = 6.8
solving
c + 3d = 4.86
1.2c + 6d = 6.8
we get
c = 3.65
d = 0.4033
so
the value of c is 3.65
now
we can see that
for 1 mole of C6H1206 taken 3.65 moles of biomass is produced
now
Yx/s = moles of biomass formed / moles of substrate taken
Yx/s = 3.65 / 1
Yx/s = 3.65
so
the value of Yx/s is 3.65 mol/mol
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