Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Yeast is used to produce a direct-energy-coupled extracellular product (P) using

ID: 1024782 • Letter: Y

Question

Yeast is used to produce a direct-energy-coupled extracellular product (P) using glucose as the carbon source that can be described by the following chemical equation. 1.14 moles of CO2 and 2.6 moles of water are produced per mole of glucose consumed.

C6H12O6 + b NH3 + a O2 —> c CH1.8O0.5N0.2 (biomass) + d C3H6O3 (P) + e H2O + f CO2

What is the yield of biomass from substrate (YXS) in molar units?

Stoichiometry. Yeast is used to produce a direct-energy-coupled extracellular product (P) using glucose as the carbon source that can be described by the following chemical equation. 1.14 moles of CO2 and 2.6 moles of water are produced per mole of glucose consumed. 12 b NH3 a O2 c CH18 oo.5No.2 (biomass) +d C3H603 (P) e H20+ f CO What is the yield of biomass from substrate (Yxs) n molar units?

Explanation / Answer

consider the unbalanced reaction

C6H12O6 + b NH3 + a O2 —> c CH1.8O0.5N0.2 (biomass) + d C3H6O3 (P) + e H2O + f CO2

given

1.14 moles of C02 and 2.6 moles of water are produced

so

f = 1.14

e = 2.6

the reaction becomes

C6H12O6 + b NH3 + a O2 —> c CH1.8O0.5N0.2 (biomass) + d C3H6O3 (P) + 2.6 H2O + 1.14 CO2

now

using conservation principle

number of C atoms in reactants = number of C atoms in products

1 x 6 = ( c x 1) + ( d x 3) + 1.14

6 = c + 3d + 1.14

c + 3d = 4.86

now

number of N atoms in reactants = number of N atoms in products

b = c x 0.2

c = 5b

now

number of H atoms in reactants = number of H atoms in products

so

1 x 12 + ( b x 3) = ( c x 1.8) + ( d x 6) + ( 2.6 x 2)

12 + 3b = 1.8c + 6d + 5.2

6.8 + 3b = 1.8c + 6d

now

b = 0.2 c

so

6.8 + ( 3 x 0.2c) = 1.8c + 6d

6.8 + 0.6c = 1.8c + 6d

1.2c + 6d = 6.8

solving

c + 3d = 4.86

1.2c + 6d = 6.8

we get

c = 3.65

d = 0.4033

so

the value of c is 3.65
now

we can see that

for 1 mole of C6H1206 taken 3.65 moles of biomass is produced

now

Yx/s = moles of biomass formed / moles of substrate taken

Yx/s = 3.65 / 1

Yx/s = 3.65

so

the value of Yx/s is 3.65 mol/mol