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ID: 1025051 • Letter: #

Question

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Explanation / Answer

The balanced equation is

2 HCl + Ba(OH)2 -----> BaCl2 + 2 H2O

number of moles of Ba(OH)2 = 31.2 g / 171.34 g/mol = 0.182 mole

from the balanced equation we can say that

1 mole of Ba(OH)2 produces 1 mole of BaCl2 so

0.182 mole of Ba(OH)2 will produce

= 0.182 mole of Ba(OH)2 *(1 mole of BaCl2 / 1 mole of Ba(OH)2)

= 0.182 mmole of BaCl2

mass of 1 mole of BaCl2 = 208.23 g

so the mass of 0.182 mole of baCl2 = 37.9 g

Therefore, the mass of BaCl2 produced would be 37.9 g