(°C/ m ) Normal freezing point ( °C) (°C/ m ) Normal boiling point ( °C) Solvent

Question

(°C/m)

Normal freezing

point (°C)

(°C/m)

Normal boiling

point (°C)

Solvent Formula Kf value*

(°C/m)

Normal freezing

point (°C)

Kb value

(°C/m)

Normal boiling

point (°C)

water H2O 1.86 0.00 0.512 100.00 benzene C6H6 5.12 5.49 2.53 80.1 cyclohexane C6H12 20.8 6.59 2.92 80.7 ethanol C2H6O 1.99 –117.3 1.22 78.4 carbon
tetrachloride   CCl4 29.8 –22.9 5.03 76.8 camphor   C10H16O 37.8 176
If a 0.610 m aqueous solution freezes at-3.00 , what is the van't Hoff factor, i, of the solute? Kf values can be found here. Number

Explanation / Answer

Normal freezing point of water = 0.00 oC
Actual freezing point = -3.00 oC
So,
delta Tf = 3.00 oC

use:
delta Tf = i*Kf*m
3.00 = i*1.86*0.610
i = 2.64

Answer: 2.64

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