Tran × Soci × Rest × For Y × takeAssignment/takeCovalentActivity.do?locator-assi

Question

Tran × Soci × Rest × For Y × takeAssignment/takeCovalentActivity.do?locator-assignment-take Use the References to access important values if needed for this question. Match the following aqueous solutions with the appropriate letter from the column on the right. 1.0.19 m Cr(NO3)2 2. 0.25 m NH4CI 3. 0.24 m NaC 4. 0.53 m Glucose(nonelectrolyte) A. Highest boiling point B. Second highest boiling point C. Third highest boiling point D. Lowest boiling point Submit Answer Retry Entire Group 9 more group attempts remaining

Explanation / Answer

delta Tb = i*kb*m
So, the one with greater i*m value will have higher boiling point

1)
i =3 Cr(NO3)2 dissociates into 1 Cr2+ and 2 NO3-
i*m = 3*0.19 = 0.57

2)
i = 2 as it dissociates into 1 NH4+ and 1 Cl-
i*m = 2*0.25 = 0.50

3)
i = 2
i*m = 2*0.24 = 0.48

4)
i=1 since this is non electrolyte
i*m = 1*0.53 = 0.53

Answer:
1 —> A
2 —> C
3 —> D
4 —> B

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