it View History Bookmarks Window Help try.com 12-General Chemistry Section 08 Sp

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it View History Bookmarks Window Help try.com 12-General Chemistry Section 08 Spring Semester 2018 co i se Post Lecture Homework Chapter 06 Kinetic Energy 1 of 13 Constants Period, Tette Part A A goose is lying south for the winter atl a constant speed. Keep in mind that one mile is 161 km, and one pound 454 g The gose has a mass of 23 9 b (pounds) and is fying at 116 ules/h imles per hour) What a the kinesic energy of the goose in joules? Enter your answer numerically in joules. View Available His t Incerrect: Try Again; 4 attempts remaining 898 8 5

Explanation / Answer

Kinetic energy = KE = (1/2)mV^2

where

m = mass of the goose = 23.9 lb (given)
V = velocity of the goose = 11.6 mph (given)

NOTE -- since the conversion factors, one mile is 1.61 km , and one pound is 454 g, then we get the KE in the unit of joule.

KE = (1/2)(23.9/2.2)(11.6*1.61*1000/3600)^2

KE = 146.19 joules .

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