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O cvg.cengagenow.com/ilrn/takeAssignment/takeCovalentActivity.do?locator=assignm

ID: 1026083 • Letter: O

Question

O cvg.cengagenow.com/ilrn/takeAssignment/takeCovalentActivity.do?locator=assignment-take itakeAssignmentSessionLocator=assignment-take 165 1. Titration Curve: Weak Acid/Stron... 1 pt treg [Review Topics] [References) Use the References to access important values if needed for this question. 2. Titration Curve: Weak Base/Stro... 1 pr treg A 29.7 ml sample of 0.220 M trimethylamine, (CH3)3N, is titrated with 0.307 M hydrochloric acid. cQuestion Question At the equivalence point, the pH is Use the Tables link in the References for any equilibrium constants that are required. Submit Answer Retry Entire Group 9 more group attempts remaining Progress: 0/2 groups Due Mar 11 at 11:55 PM Finish Assignment Save and Exit

Explanation / Answer

millimoles of amine = 29.7 x 0.220 = 6.534

6.534 millimoles acid must be added to reach equilibrium

6.534 = V x 0.307

V = 21.28 mL acid must be added

total volume = 21.28 + 29.7 = 50.98 mL

[salt] = C = [6.534 / 50.98] = 0.128 M

for salts of weak base and strong acids

pOH = 1/2 [pKw + pKa + log C]

pKa = 4.19 standard value fro trimethyl amine

pOH = 1/2 [14 + 4.19 + log 0.128]

pOH = 8.65

pH = 14 - 8.65

pH = 5.35