Map If you were going to graphically determine the activation energy of this rea
ID: 1027394 • Letter: M
Question
Map If you were going to graphically determine the activation energy of this reaction, What points would you plot? Consider this reaction data products Number Number T (K) k (s-1) 275 725 point 1:0.00363 0.992 To avoid rounding errors, use at least three significant figures in all values 0.371 0.702 Number Number point 2: 0.00137 0.353 Determine the rise, run, and slope of the line formed by these points rise run slope Number Number Number 0.638 0.00226 212 What is the activation energy of this reaction? Number 0.1768 x 104J/molExplanation / Answer
We need to plot lnK on y axis and 1/T on x axis
K = 0.371
ln K = ln (0.371) = -0.99155
T = 275.0
1/T = 0.00364
point 1 is:
x = 0.00364
y = -0.99155
K = 0.702
ln K = ln (0.702) = -0.35382
T = 725.0
1/T = 0.00138
point 2 is:
x = 0.00138
y = -0.35382
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rise = (y1-y2) = -0.99155 - -0.35382 = -0.63773
rise = (X1-X2) = 0.00364 - 0.00138 = 0.00226
slope = rise/run
= -0.63773/0.00226
= -282.55041
----------------------------------------------------------------------------
use
slope = - Ea/R
= -282.55041 = -Ea/8.314
Ea = 2349 J/mol
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