https://digital 16235 CHPHw 120e/17 out of 26 0 This is a Numeric Entry question
ID: 102763 • Letter: H
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https://digital 16235 CHPHw 120e/17 out of 26 0 This is a Numeric Entry question/tis worth 1 point / You have unlimited attempts/There is no attempt penalty 15 Question (1 point) The complete combustion of 1.15 g of cinnamaldeyde (CyH0,one of the compounds in produced an increase in temperature of 13.9 C cinnamon) in a bomb calorimeter (Calerimante 3.85 kurc) 1st attempt See Periodic Table Calculate the molar enthalpy of combustion of cinnamaldehyde (4H.oms) (in kilojoules per mole of cinnamaldehydel. kJ/mol 1520>Explanation / Answer
Q15.
m = 1.15 g of cinnamaldeyde in Ccal = 3.85 kJ/°C procues dT = +13.9°C
a)
calcualte molar enthalpy of combustion
Hcomb = Qcomb/n
Qcomb = -Qcal
Qcal = CCal*dT = 3.85*13.9 = 53.515 kJ
mol = mass/MW = 1.15/132.16 = 0.00870 mol
HRXN = -53.515/0.00870
HRXN = -6151.14 kJ/mol
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