for the following chemical reaction, what mass of lead(ll) iodide (in grams) wil

Question

for the following chemical reaction, what mass of lead(ll) iodide (in grams) will be produced from 5.07 mol Of potassium iodide? gle Slides Fight Club Summary from LitCharts | The creators of SparkN. condo - Google Sea te University, Fullerton-CHEM 115-Spring18-OVERSTREET Activities and Due DatesHW16 3/15/2018 11:55 PM Print 3/7 Gradebo il Calculator Correct -Periodic Table Question 7 of 7 Sapling Learning For the f from 5.07 mol of potassium iodide? chemical reaction, what mass of lead(lI) iodide (in grams) will be produced 2K1 + Pb(NO3), Pbl: +2KNo, Number 1168 Correct. Previcus @ Vew Solution @ Check Answer Next Ext View Solution Check Answer Exit 8 337 15

Explanation / Answer

from equation,

   2 mol KI = 1 mol Pb(NO3)2 = 1 mol PbI2

No of mol of KI taken = 5.07 mol

No of mol of PbI2 formed = 5.07*1/2 = 2.535 mol

amount of PbI2 formed = n*Mwt

                       = 2.535*461.03

                       = 1168.7

    answer: 1169 g

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