PrintCalcul lator Periodic Table Question 13 of 13 Available From Not Set Due Da

Question

PrintCalcul lator Periodic Table Question 13 of 13 Available From Not Set Due Date: Points Possible: 100 Grade Category: Homework 12/8/2017 11:55 Sapling Learning Gold-198 has a half-life of 2.7 days. How much of a 122.0 mg gold-198 sample will remain after 13.5 days? Number Policies: Homework Im You can check your answers. You can view solutions when you cc give up on any quesion You can keep trying to answer each until you get it right or give up. You lose 5% of the points available answer in your question for each in attempt at that answer eTextbook Help With This Topic O Web Help & Videos Previous Give Up & View Solution O Check Answer @Next Exit Technical and Hint

Explanation / Answer

k = 0.693/(half life)
= 0.693/2.7
= 0.257 days^-1
use,
ln([A]0/[A]) = k*t
ln(122.0/[A]) = 0.257*13.5
ln(122.0/[A]) = 3.47
(122.0/[A]) = 32.1
[A] = 3.80 mg

Answer : 3.80 mg

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