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Ti (s) + 2F2 (g) —> TiF4 (s) What is the maximum amount of TiF4 in grams that ca

ID: 1028700 • Letter: T

Question

Ti (s) + 2F2 (g) —> TiF4 (s)
What is the maximum amount of TiF4 in grams that can be formed when 2.40g of Ti is allowed to react with 1.60 g of F2 ?
(Please explain every step) Ti (s) + 2F2 (g) —> TiF4 (s)
What is the maximum amount of TiF4 in grams that can be formed when 2.40g of Ti is allowed to react with 1.60 g of F2 ?
(Please explain every step)
What is the maximum amount of TiF4 in grams that can be formed when 2.40g of Ti is allowed to react with 1.60 g of F2 ?
(Please explain every step)

Explanation / Answer

      Ti (s) + 2F2 (g) —> TiF4 (s)

    no of moles of Ti    = W/G.A.Wt

                                 = 2.4/47.867    = 0.05moles

no of moles of F2     = W/G.M.Wt

                               = 1.6/38   = 0.042moles

1 mole of Ti react with 2 moles of F2

0.05 moles of Ti react with = 2*0.05/1 = 0.1 moles of F2

F2 is limting reactant

2 moles of F2 react with Ti to gives 1 mole TiF4

0.042 moles of F2 react with Ti to gives = 1*0.042/2   = 0.021 moles of TiF4

mass of TiCl4    = no of moles * gram molar mass

                       = 0.021*189.68   = 3.98g of TiCl4

The maximum mass of TiCl4 = 3.98g >>>>answer

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